下面的函数怎么改成不用模板的调用

music

const int NUM_IN  = 4;
const int NUM_REC = 2;  // recovery

#define BUF_SIZE 1024


函数定义的地方

template<typename gtype, typename utype>
int test4(int NUM_IN, int *expected_bases) {
  //const int NUM_IN  = 10;

  const int NUM_REC = 1;  // recovery
  const int LOW_EXPONENT = 1;

  u8 data[NUM_IN + NUM_REC][BUF_SIZE];

  int high_exponent = LOW_EXPONENT + NUM_REC - 1;

  for (int i = 0; i < NUM_IN; i++) {
    // fill with zeros,
    for (int k = 0; k < BUF_SIZE; k++) {
      data[i][k] = (u8)0;
    }
    // EXCEPT write a (little endian) 1 in a different place for each file
    // In the i-th file, it is written into the i-th location
    data[i][sizeof(utype)*i] = (u8) 1;
  }
  // zero recovery
  for (int j = 0; j < NUM_REC; j++) {
    for (int k = 0; k < BUF_SIZE; k++) {
      data[NUM_IN + j][k] = (u8)0;
    }
  }


  ReedSolomon<gtype> rs_creator;

  //cout << "creator.setinput" << NUM_IN << endl;
  if (!rs_creator.SetInput(NUM_IN, cout, cerr)) {
    cerr << "rs_creator.SetInput returned false";
    return 1;
  }
  //cout << "creator.setoutput" << LOW_EXPONENT << " " << high_exponent << endl;
  if (!rs_creator.SetOutput(false, LOW_EXPONENT, high_exponent)) {
    cerr << "rs_creator.SetOutput returned false";
    return 1;
  }
  //cout << "creator.compute" << endl;
  if (!rs_creator.Compute(nlSilent, cout, cerr)) {
    cerr << "rs_creator.Compute returned false";
    return 1;
  }

  for (int i = 0; i < NUM_IN; i++) {
    for (int j = 0; j < NUM_REC; j++) {
        //cout << "creator.process " << BUF_SIZE << " " << i << " " << j <<
endl;
        rs_creator.Process(BUF_SIZE, i, &(data[i][0]), j, &(data[NUM_IN + j][0])
);
    }
  }


  // The recovery file has exponent 1 and should
  // contain each base to the power 1.
  for (int i = 0; i < NUM_IN; i++) {
    // read little-endian value
    utype v = 0;
    for (int byte_index = 0; byte_index < sizeof(utype); byte_index++) {
      u8 byte = data[NUM_IN+0][sizeof(utype)*i + byte_index];
      v |= (((utype)byte) << (byte_index*8));
    }
    int base = v;
    if (base != expected_bases[i]) {
      cerr << "base at location " << i << " did not match expected." << endl;
      cerr << "   base     = " << base << endl;
      cerr << "   expected = " << expected_bases[i] << endl;
      return 1;
    }
  }
  return 0;
}

====================

在下面的函数中被用到

  int expected_bases16[10] = {2, 4, 16, 128, 256, 2048, 8192, 16384, 4107,
32856};
  if (test4<Galois16,u16>(10, expected_bases16)) {
    cerr << "FAILED: test4(16)" << endl;
    return 1;
  }

0xAA55

有必要改么。。。